Question

......................,.,................​

Answer 1

a=6, b=2

Step-by-step explanation:

Use simplification into substitution
$\frac{a}{3} =1+\frac{2}{b}$

$a=3(1+\frac{2}{b})$

$a=3+\frac{6}{b}$

We can now plug this value of a into the second equation.

$\frac{3+\frac{6}{b} }{4} +\frac{3}{b} =3$

Get rid of fractions in the numerators and/or denominators

$\frac{3b+6}{4b} +\frac{3}{b} =3$

Then we can match the denominators

$\frac{3b+6}{4b} +\frac{12}{4b} =3$

Combine

$\frac{3b+18}{4b} =3$

Divide both sides by three

$\frac{b+6}{4b} =1$

Get rid of fractions

$b+6=4b$

Single out b

$6=3b$

$b=2$

Now we can plug it into the equation

$\frac{a}{3} -\frac{2}{2} =1$

$\frac{a}{3} =2$

$a=6$

Now we can check it;

$\frac{6}{3} -\frac{2}{2} =1$

↑CORRECT

$\frac{6}{4} +\frac{3}{2} =3$

↑CORRECT