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GREYUIT [131]
3 years ago
6

poll finds that 54% of the 600 people polled favor the incumbent. Shortly after the poll is taken, it is disclosed that he had a

n extramarital affair. A new poll finds that 50% of the 1030 polled now favor the incumbent. We want to know if his support has decreased. The test statistic is A. z = -2.57. B. z = 1.56. C. z = -1.55.
Mathematics
1 answer:
Paha777 [63]3 years ago
7 0

Answer: A. z = -2.57

Step-by-step explanation:

Let p be the population proportion of people polled favor the incumbent.

As per given , we have

H_0: p=0.54\\\ H_a: p

Sample size : n= 1030

sample proportion :  \hat{p}=0.50

Test statistic for proportion : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.50-0.54}{\sqrt{\dfrac{0.54(1-0.54)}{1030}}}\\\\= \dfrac{-0.04}{\sqrt{\dfrac{0.2484}{1030}}}\\\\=\dfrac{-0.04}{0.015529488}\approx-2.57

Hence, the  test statistic is z = -2.57 .

Thus , the correct answer is A. z = -2.57 .

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Use the information given to find a convenient class width. Then list the class boundaries that can be used to create a relative
notka56 [123]

Answer:

hello some information is missing below is the missing information

8 classes for n = 75 measurements; minimum value = 20; maximum value = 175

answer : width = 20

               class boundary : 20,40,60,80,100,120,140,160,180

Step-by-step explanation:

Using the information given the convenient class width

= (maximum value - minimum value) / number of class

= ( 175 - 20 ) / 8

= 155 / 8 = 19.375 to the nearest multiple of 5 =  20

Using the minimum value as the smallest class boundary

the class boundary will be :

20,40,60,80,100,120,140,160,180

since the maximum value 175

6 0
2 years ago
The first digit of a string of 2002 digits is a 1. Any two-digit number formed by consecutive digits within this string is divis
Umnica [9.8K]

The largest possible last digit in the string of 2002 digits and number divisible by 19 or 31 is 9.

Given the first digit of a string of 2002 digits is 1 and the two digit number formed by consecutive digits within the string is divisible by 19 or 31.

We have to tell the last largest digit of such number.

Two digit numbers divisible by 19=19,38,57,76,95.

Two digit numbers divisible by 31=31,62,93,124

Number started with 1 =19

Last digit is 9

We have said that the number should be divisible by 19 or 31 not from both and started with 1.

Hence the largest possible last digit and number divisible by 19 or 31 in this string is 9.

Learn more about digits at brainly.com/question/26856218

#SPJ4

4 0
2 years ago
18x3=y<br> What is the value of y?
Romashka [77]
If you do it on a calculator it should come up to be 54 which is the answer
5 0
3 years ago
A scientist makes an acid solution by adding drops of acid to 1.2 L of water. The final volume of the acid solution is 1.202 L.
laila [671]

Answer:

40 drops

Approximately 0.166 %

Step-by-step explanation:

It would be easier to work the same units for volume

Since there are 1000 ml in a liter

Original water volume 1.2 L = 1.2 x 1000 = 1200 mLl

The final volume of the acid-water solution = 1.202 L = 1202 mL

So total volume of acid added = 1202-1200 = 2 mL

Each drop of acid is 0.05 mL

Number of drops added = 2/.05 = 40 drops

Percent of acid in acid solution = (Volume of acid added)/(Final volume) x 100 = (2/1202) ≈ 0.00166 x 100 ≈ 0.166 %

7 0
1 year ago
What is the area of this
AveGali [126]

Answer:

12m

Step-by-step explanation:

3 0
2 years ago
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