Let x be ml of 5% soln.
let 500-x be ml of 25% soln.
.
x*.05=.05x
(500-x)*.25=125-.25x
500*.20=100
.
.05x+125-.25x=100
-.2x=-25
x=-25/-.2
x=125 ml of 5% soln.
500-x=375 ml of 25% soln.
.
Check:
125*.05= 6.25
375*.25=93.75
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========100
Answer:
Getting a multiple of 5 is the least likely outcome.
Step-by-step explanation:
We spin a spinner that has 8 equal-sized sections numbered 1 - 8.
We have to find which is the least likely to occur.
The number is even when outcomes are 2,4,6 or 8.
Number of outcomes = 4
If the number is less than 3, the number of possible outcomes are 2 that is 1 and 2.
If the number is greater than 3 , number of possible outcomes is 5 which are 4,5,6,7 and 8.
If the number is a multiple of 5, only 1 outcome is there which is 5 itself.
Hence getting a multiple of 5 is the least likely outcome.
To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
Answer: The domain is [0, 4] when the graph is negative.
