Answer:
Molar mass = 254.60g/mol
Step-by-step explanation:
Mass = 8.02g
Volume = 812mL = 0.812L
Pressure (P) = 0.967atm
Temperature of the gas = 30°C = (30 + 273.15)K = 303.15K
Molecular weight = ?
To solve this question, we'll have to use ideal gas equation, PV = nRT
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant = 0.082J/mol.K
T = temperature of the gas
PV = nRT
n = PV / RT
n = (0.967 * 0.812) / (0.082 * 303.15)
n = 0.7852 / 24.8583
n = 0.0315 moles
Number of moles = mass / molarmass
Molarmass = mass / number of moles
Molar mass = 8.02 / 0.0315
Molar mass = 254.60g/mol
The molar mass of the gas is 254.60g/mol
Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
(3.5, 16)
Midpoint Formula is
((x1+x2)/2, (y1+y2)/2)
Answer:
102.5, 103.5
Step-by-step explanation:
a+a+1=206
2a+1=206
2a=205
a=102.5
103.5
I think there is a bug here. They can't be whole numbers.
Answer:
EFD
Step-by-step explanation:
Just follow the marks on the triangle.