Answer:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Step-by-step explanation:
Equation I: 4x − 5y = 4
Equation II: 2x + 3y = 2
These equation can only be solved by Elimination method
Where to Eliminate x :
We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I
Hence:
Equation I: 4x − 5y = 4 × 2
Equation II: 2x + 3y = 2 × 4
8x - 10y = 20
8x +12y = 6
Therefore, the valid reason using the given solution method to solve the system of equations shown is:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
$12.89 should be the answer bc 4.5+2.25=6.75 and 87 divided by 6.75 is 12.888888 so i would either round up or down
5/6 of the paper is devoted to news and pictures
first I made the fraction have equal denominators which was 6 by doing that I multiplyed the numerator and the denominator
1/2
1×3=3
2×3=6
therefore 1/2 being equivalent to 3/6
1/3
1×2=2
3×2=6
therefore 1/3 being equivalent to 2/6
now you would be able to add the numerators, so 2+3=5
therefore being 5/6 of the paper is devoted to news and pictures
Answer:
X=-4
Step-by-step explanation: