Answer:
The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Step-by-step explanation:
The area for a rectangle is given by the formula:

Where <em>w</em> is the width and <em>l</em> is the length.
We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.
First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>
![\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BdA%7D%7Bdt%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cleft%5Bw%5Cell%5D)
By the Product Rule:

Since we know that dl/dt = 6 and that dw/dt = 5:

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.
Answer:
-3x - 5
Step-by-step explanation:
Answer:5 7/18
Step-by-step explanation:
7 2/9 - 1 5/6
65/9-1 5/6
65/9-11/6
97/18
5 7/18
KD is congruent to AT as:
<h3>angles are of equal measure</h3><h3>sides KD and TA are equal</h3><h3>sides DT and KA are equal</h3>
The figure is kite as has two pairs of same sides.
<h3>They are constructed in a way of having same angle.</h3>
8.8 *10^3 (2 sig fig)
2.9 *10^3 (2 sig fig)