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shepuryov [24]
3 years ago
12

PLEASE HURRY!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
aksik [14]3 years ago
7 0

Answer:

(5n²+10xn)(2n-3)

Step-by-step explanation:

10n³-15n²+20xn²-30xn

1. Factor by grouping

(10n³-15n²)+(20xn²-30xn)

2. Pull out Greatest Common Factor from each Pair

5n²(2n-3)+10xn(2n-3)

3. Rewrite Factored Expression Properly

(5n²+10xn)(2n-3)

Answer:

=(5n²+10xn)(2n-3)

Tell me if this helps

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First: work out the difference (increase) between the two numbers you are comparing.

Increase = New Number - Original Number

Then:  divide the increase by the original number and multiply the answer by 100.

% increase = Increase ÷ Original Number × 100

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Hurrrryyyyy plllzzz. Determine the equation of the line that passes through the given points
pashok25 [27]
<h2>Answer:</h2>

y = 2

<h2>Step-by-step explanation:</h2>

To determine the equation of the line that passes through (10,2) and (-3,2), we need to determine the slope of the line. Then substitute the slope and any given point in point slope form to obtain the equation of the line.

<h3>Finding the Slope of the line:</h3>

\implies \text{Slope} = \dfrac{\text{Rise}}{\text{Run}} = \dfrac{y_{2} - y_{1} }{x_{2} - x_{1}  }

\implies \text{Slope} = \dfrac{y_{2} - y_{1} }{x_{2} - x_{1}  }

<u>Substitute the coordinates of the given points:</u>

\implies \text{Slope} = \dfrac{2 - 2}{-3 - 10  }

<u>Simplify the equation to determine the slope:</u>

\implies \text{Slope} = \dfrac{0}{-3 - 10  }

∴ 0 divided by ANY number is ALWAYS 0.

\implies \text{Slope} =0

<h3>Finding the equation of the line:</h3>

Point slope form formula: y - y₁ = m(x - x₁)

  • x₁ and y₁ are the coordinates of any given point.
  • m is the slope

<u>Substitute the values in the point slope form:</u>

\implies \text{Equation of line:} \ y - y_{1}  = m(x - x_{1} )

\implies \text{Equation of line:} \ y - 2  = 0(x - 10)

<u>Simplify the equation to determine the equation of the line:</u>

∴ Any number multiplied by 0 is 0.

\implies \text{Equation of line:} \ y - 2  = 0

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\implies \text{Equation of line:} \ y   = 2

Thus, the equation of the line is y = 2.

5 0
2 years ago
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