Question

Ten samples of a process measuring the number of returns per 100 receipts were taken for a local retail store. The number of returns were 10, 9, 11, 7, 3, 12, 8, 4, 6, and 11. Find the standard deviation of the sampling distribution for the p-bar chart. 0.0863 0.081 0.0273 There is not enough information to answer the question. 8.1

Answer 1

Answer:

0.0273

Step-by-step explanation:

np  n

10  100

9    100

11   100

7    100

3   100

12  100

8   100

4    100

6    100

11   100

pbar=sumnp/sumn

pbar=10+9+11+7+3+12+8+4+6+11/10+10+10+10+10+10+10+10+10+10

pbar=81/1000

pbar=0.081

nbar=sumn/k=1000/10=100

$Standard deviation for pbar chart=\sqrt{\frac{pbar(1-pbar)}{nbar} }$

$Standard deviation for pbar chart=\sqrt{\frac{0.081(0.919)}{100} }$

$Standard deviation for pbar chart=\sqrt{\frac{0.0744}{100} }$

$Standard deviation for pbar chart=\sqrt{0.0007444 }$

Standard deviation for p-chart=0.0273