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3 years ago

What is an asexual structure where spores develope?

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

8 0

An asexual structure where spores develop is Sporangium

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Help me... :/<br><br> Find the measure of each exterior angle of a regular 45-gon.

GuDViN [60]

Answer:

7740° / 45

Step-by-step explanation:

The sum of the interior angles is given by this formula: (n - 2) * 180°. So a regular 45-gon would have interior angles that add up to: (45 - 2) * 180°. = 43 * 180°. = 7740°. Now divide that by the 45 angles to find the measure of one interior angle

hope that helped :(

7 0

3 years ago

What's the answer of 13846+8273636-3763x8273736

ipn [44]

13846+8273636
= 8287482

8287482-3763
=8283719

8283719x8273736
=6.8537304^13

7 0

3 years ago

Xxx’s recipe from oatmeal muffins calls for 2 1/2 cups of oatmeal and makes one dozen muffins.

sasho [114]

Answer:18.75

Because if you combine each group of dozens you can then do 5x2.5 which equals 12.5 so then you do 1.5 of 2.5 and get 6.25

5 0

2 years ago

Angle DOF and angle GOH are vertical angles. What's the measure of angle DOF if the measure of angle GOH is 58°? A. 122° B. 302°

natulia [17]

Answer: C

<u>Step-by-step explanation:</u>

1. DOF and GOH are vertical angles 1. Given

2. m∠DOF = m∠GOH 2. Vertical Angles Theorem

3. ∠DOF = 58° 3. Given

4. 58° = m∠GOH 4. Substitution

4 0

3 years ago

The first task of the Segment Two Honors Project is to select the Power Pill study participants’ groups and research board offic

Tatiana [17]

Answer:

Part 1: There are 4.7*10^21 ways to select 40 volunteers in subgroups of 10

Part 2: The research board can be chosen in 32760 ways

Step-by-step explanation:

Part 1:

The number of ways in which we can organized n elements into k groups with size n1, n2,...nk is calculate as:

$\frac{ n!}{ n1!*n2!*...*nk! }$

So, in this case we can form 4 subgroups with 10 participants each one, replacing the values of:

n by 40 participants
k by 4 groups
n1, n2, n3 and n4 by 10 participants of every subgroups

We get:

$\frac{ 40!}{10!*10!*10!*10!} = 4.7*10^{21}$

Part 2:

The number of ways in which we can choose k element for a group of n elements and the order in which they are chose matters is calculate with permutation as:

$nPk = \frac{ n!}{(n-k)!}$

So in this case there are 4 offices in the research board, those are director, assistant director, quality control analyst and correspondent. Additionally this 4 offices are going to choose from a group of 5 doctors.

Therefore, replacing values of:

n by 15 doctors
k by 4 offices

We get:

$\frac{ 15!}{ (15-4)! } = 32760$

7 0

3 years ago

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