3 years ago

What is an asexual structure where spores develope?

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

8 0

An asexual structure where spores develop is Sporangium

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goldenfox [79]

Answer:

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3 years ago

What is a function ?

tia_tia [17]

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3 years ago

Mrs. Saddler and her family go out for dinner. Their bill was $55.25. Mrs. Saddler leaves a 18% tip. What is Mrs. Saddler’s tota

olchik [2.2K]

You multiply 55.25 by 0.18. You get 9.945 and then you add it to 55.25. You should get 65.195. Round it to $65.20. That's your answer.

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3 years ago

If one root of the equation is 4x^2- 2x+p-4 be the reciprocal of other. then find the value of p

SashulF [63]

Answer:

p = 8

Step-by-step explanation:

Let one root of the eqn. be alpha . Other root is 1/alpha .

We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant & "a" is the co-efficient of x^2.

Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )

$\frac{c}{a} = 1\\=> \frac{p - 4}{4} = 1\\=> p - 4 = 4\\=> p = 4 + 4 = 8$

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4 years ago

Rewrite by completing the square 2x^2+7x+6=0

Kitty [74]

Answer:

$2x^2+7x+6=0\\\\2(x^2+\frac72x+3)=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2-(\frac74)^2+3]=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2]-2(\frac74)^2+6=0 \\\\2(x+\frac74)^2-2\cdot\frac{49}{16}+6=0\\\\2(x+\frac74)^2-\frac{49}8+\frac{48}8=0\\\\2(x+\frac74)^2-\frac18=0$

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3 years ago