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Lerok [7]
3 years ago
8

What is an asexual structure where spores develope?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
8 0
An asexual structure where spores develop is Sporangium
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What is the solution to the system of equations below?<br> -20 + y = 2<br> 20 + 3y = 6
steposvetlana [31]
-20 + y = 2
y = 22

20 + 3y = 6
y = 14/3
4 0
3 years ago
Weekand homework and i need help
Lelechka [254]

Answer:

C. 54

Step-by-step explanation:

36/60=.6

90*.6=54

8 0
2 years ago
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6x + 5y = 4<br> - 6x + y = 20
Masja [62]

Answer:

x = -8/3

y = 4

Step-by-step explanation:

I assume you want to solve for x and y.

The best way to do this with the two formulas given is elimination. This means add the two equations together.

6x + 5y = 4

-6x + y = 20

The 6 x and -6x will cancel each other. By adding the like terms of the two together you will come out with

6y = 24

Now solve for y by dividing both sides by the 6.

y = 24/6 = 4

Now that we have y, you can plug it into one of the equations and solve for x.

Let's use -6x + y =20.

So plug in the 4 for y to get -6x + 4 = 20

Subtract the 4 from both sides then solve for y by dividing both sides by the -6.

-6x = 16

x = -16/6

You can reduce that down so that x = -8/3.

5 0
4 years ago
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To join a gym, you have to pay an initial fee of $50 and $30 per month. Write an equation representing total cost (t).
Vladimir [108]
50+30m= t

m: number of months
t: total
6 0
3 years ago
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If b = 5, what is the value of<br>each expression?<br>10 + 7b<br>76 + 10​
Kipish [7]

Answer:

10+7b= 45

76+10=86

Step-by-step explanation:

5 0
3 years ago
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