A^2-8a-48=0
factor
(a+4)(a-12)=0
set each equal to 0
a+4=0 a-12=0
a=-4,12
Answer:
c & d
Step-by-step explanation:
Factor x^2 + 3 x − 10 using the AC method
Answer:
8 13 14 15 18.
Step-by-step explanation:
The median (the middle number) is 14 so we have
x x 14 x x where x is a single number with each number being different (as there is no mode).
The mean is 13.6 so we have the total numbers
= 13.6 * 5 = 68.
The 4 numbers left must total 68-14 = 54 and the difference between the highest and lowest is 10.
I sense that the lowest and highest will add up to about 1/2 of 54 so:
Try 8 and 18 for these last 2 numbers
The list would be 8 x 14 x 18.
The 2 numbers left will add up to 54 - 26 = 28 . One of these must be < 14 and the other > 14. 13 and 15 would fit.
So a possible data set is:
8 13 14 15 18.
Answer:
Step-by-step explanation:
Let 
first consecutive number
(
is the first number, 
would be the second consecutive number of the sequence, and 
would be the third)
the consecutive numbers that sum up to 
are 
and 
Hope this helps :)
So 2/3 sum
two fractions
denominator NOT 3
so sum can be 4/6
and so 2/6 + 2/6 = 4/6 or 2/3
Hope this helps ;)
