This is the number of combinations of 2 from 23
23C2 = 23! / 2! 21!
A quick way to do this is 23*22 / 2 = 253
Answer:
D. The sun of angles A and B are supplementary to angle C
Answer:
Step-by-step explanation:
p(x) = |x|
in : R let : y = |x|
calculate : x
y² = |x| ²
y² = x²
y² - x²= ( y - x)( y +x) by identity
y = x or y = - x
the inverse : y = x or y = - x
conclusion : the inverse is : g(x) = |x|
You must do 6 to the second power then plug in 3 for M which gives you 36/2(3), multiply 2 times 3 to get 6 then divide. Your answer is 6.
