I really need help on this question!!!ASAP!!!(Feel free to show your work :)

Mathematics

1 answer:

Airida [17]3 years ago

8 0

Okay, so divide the circle in half and they divide one of those halves in half again. The largest chunk is 30 and the other two are 15

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By which smallast number must the following number be divided so that the quotient is a perfect cube

jenyasd209 [6]

Answer:

Step-by-step explanation:

8640/60 is 144. 144 is a perfect square. 12*12 is 144

8 0

3 years ago

Read 2 more answers

Layla has the following data:

ratelena [41]

The answer would be 25 because to find the range you have to subtract the highest number with the lowest number which would be 29-25=4

6 0

3 years ago

Let C be the positively oriented square with vertices (0,0), (1,0), (1,1), (0,1). Use Green's Theorem to evaluate the line integ

liq [111]

Answer:

1/2

Step-by-step explanation:

The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that

$\int\limits_C {L(x,y)} \, dx + {M(x,y)} \, dy = \int\limits^1_0\int\limits^1_0 {(Mx - Ly)} \, dxdy$

Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.

Mx(x,y) = d/dx 8x²y = 16xy
Ly(x,y) = d/dy 7y²x = 14xy

Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy$

We can compute the double integral by applying the Barrow's Rule, a primitive of 2xy under the variable x is x²y, thus the double integral can be computed as follows

$\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy = \int\limits^1_0 {x^2y} |^1_0 \,dy = \int\limits^1_0 {y} \, dy = \frac{y^2}{2} \, |^1_0 = 1/2$