Since opposite exterior angles are congruent I would plug in numbers for X till you find a number that goes into both and gets you the same product.
Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer: answer is C because if you do 2x9 abd 2x3 you 18c-6d and you cant subtract thise cause they have different variables
Step-by-step explanation:
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its x<-2
