Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
We will be using simultaneous equations to solve this problem.
First we will establish the equations which we will be using as displayed below:
Equation No. 1 -
A + B = 90°
Equation No. 1 -
A = 2B + 12
To begin with, let's make ( A ) the subject in the first equation as displayed below:
Equation No. 1 -
A + B = 90
A = 90 - B
Next we will substitute the value of ( A ) from the first equation into the second equation and solve for ( B ) as displayed below:
Equation No. 2 -
A = 2B + 12
( 90 - B ) = 2B + 12
- B - 2B = 12 - 90
- 3B = - 78
B = - 78 / - 3
B = 26°
Then we will substitute the value of ( B ) from the second equation into the first equation to solve for ( A ) as displayed below:
A = 90 - B
A = 90 - ( 26 )
A = 64°
ANSWER:
Therefore, the answer is:
A = 64°
B = 26°
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The concept of radicals and radical exponents is tricky at first, but makes sense when we look into the logic behind it.
When we write a radical in exponential form, like writing √x as x^(1/2), we are simply putting the power of the radical in the denominator (bottom number) of the exponent, and the numerator is the power we raise the exponent to, or the power that would be inside the radical.
In our example, √x is really ²√(x¹), or the square root of x to the first power. For this reason, we write it as x^(1/2).
Let's say we wanted to write the cubed root of x squared, in exponential form.
In radical form, it would look like this:
³√(x²) . This means we square x, and then take the cubed root.
In exponential form, remember that we take the power of the radical (3), and make that the denominator of the exponent, and keep the numerator as the power that x is raised to (2).
Therefore, it would be x^(2/3), or x to the 2 thirds power.
Just like when multiplying by a fraction, you multiply by the numerator and divide by the denominator, in exponential form, you raise your base number to the power of the numerator, and take the root of the denominator.
Answer:
Option B is correct .
Step-by-step explanation:
According to Question , both the graph have same shape . If we look at the the first graph it cuts x - axis at (0 , 2) and ( 0 , -2) . Hence x = 2 and -2 are the zeroes of the equation .
And ,the given function is ,
<u>Hence ,we can can see that x = </u><u> </u><u>2</u><u> </u><u>and</u><u> </u><u>(</u><u>-</u><u>2</u><u>)</u><u> </u><u>are</u><u> </u><u>the</u><u> </u><u>zeroes </u><u>of </u><u>graph</u><u>. </u><u> </u>
This implies that if we know the zeroes , we can frame the Equation.
On looking at second parabola , it's clear that cuts x - axis at ( 1, 0 ) and (-1,0). So , 1 and -1 are the zeroes of the quadratic equation . Let the function be g(x) . Here , a and ß are the zeroes.
<u>Hence </u><u>option </u><u>B</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u> </u><u>.</u>
Answer:
No, 55 and 101 are not multiples of 2, 3 and 9
Step-by-step explanation:
