Question

Help with this needed

Answer 1

$12x ^{2}-7x -= 0 \\ \\ x = \frac{7 + \sqrt{481} }{24} \: or \: x = \frac{7 - \sqrt{481} }{24} \\ \: b. \: -7 \\ \\3x^{2} + 3x + 2 = 0 \\ c. \: no \: real \: solutions$

Answer 2

ANSWER

1. -7

2. no real solution

EXPLANATION

1. The given quadratic equation is:

$12 {x}^{2} - 7x - 9 = 0$

Comparing this to

$a{x}^{2} + bx + c= 0$

we have a=12, b=-7 and x=-9.

Therefore the value of b is -7

2. The given quadratic equation is

$3{x}^{2} + 3x + 2= 0$

We have a=3,b=3 and c=2.

The discriminant of this equation is

$D= {b}^{2} - 4ac$

$D= {3}^{2} - 4(3)(2)$

$D= 9- 24 = - 15$

Since the discriminant is negative, the equation has no real roots.