Given, the length of one of diagonal of quadrilateral is 10 cm and perpendicular drawn from the opposite vertices to this diagonal are the length of 2.8 cm and 4.2 cm.

A diagonal divided a quadrilateral into two triangle.

Therefore the area of the quadrilateral

= sum of the area of the triangles

$=(\frac{1}{2}\times 10\times 2.8+ \frac{1}{2}\times 10\times 4.2)$ cm² [ area of a triangle $= \frac{1}{2}\times base\times height$ ]

=35 cm²

3 0

3 years ago

8.) The following table shows the monthly

Vladimir79 [104]

Answer:

from June to July

Step-by-step explanation:

the biggest change was $70

4 0

3 years ago

Determine the missing side lengths

svetlana [45]

Answer:

Given that is a 45-45 triangle, the hypotenuse should be <em>x</em> $\sqrt{2}$ , so in this case. The hypotenuse should be 3 $\sqrt{2}$ , and the other side lengths 3. I see no other way of it going other than that one; I hope I helped at least a bit!

Step-by-step explanation:

6 0

3 years ago

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Which expressions record the product of exactly two factors ?

Natasha2012 [34]

Answer:

B. 5(x + y)

C. (x - y)(x + y)

4 0

3 years ago

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