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2 years ago

PLEASE HELP!!!!!! ILL GIVE BRAINLIEST *EXTRA 40 POINTS** !! DONT SKIP :((

Mathematics

1 answer:

jeyben [28]2 years ago

7 0

Answer:

No.

Step-by-step explanation:

When you plug in -6 for x, and 6 for y, like this 5 (-6) + 12 (6) = -15, it does not equal -15, but 42.

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The base of a 13 foot ladder is 5 feet away from the wall. How far up the wall does the ladder reach? A)8 feet B)10 feet C)12 fe

Lisa [10]

You are solving for the height. Use the formula:

c² - b² = a² in which c = hypotenuse

(13)² - (5)² = a²

Simplify

169 - 25 = a²

144 = a²

Isolate the a. Root both sides

√144 = √a²

a = √144

a = √(12 x 12)

a = 12

C) 12 feet is your answer

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3 years ago

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Can someone tell me everything they know about Introducing Proportional Relationships?

Nookie1986 [14]

Answer:

1.Radius if half of diameter

2.If you want to get to circumference it diameter x 3.14

3.To find area of circle r x r x 3.14

4.From circumferenc to diameter it is circumfrence

divided by 3.14

4 0

3 years ago

PLEASE HELP ME PLEASE WITH THIS ALGEBRA QUESTION!! THANK YOU

max2010maxim [7]

WHATS THE QUESTION i can’t help if there’s no question

4 0

2 years ago

Could i please get this by today?

aleksley [76]

Answer:

ex.1: 9000$ ex.2: The only way it would work is 9x(-9)= -18+5= -13. ex.3: around 4 hours ex.4: I'm so sorry, I don't understand that. I failed you on that one someone else can answer it ex.5: 149 lbs.

Step-by-step explanation:

Ex1: Is he earns 1/6 of his sales, then it's 1500x6, which is 9000$.

Ex2: Shown in answer.

Ex3: !60+38=198+18=236+38=312.

Ex4: :'(

Ex5: Ruby is 3 lbs less than half her mom's weight, so it would be 76x2=152, then 152-3=149.

4 0

3 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago