Please ignore the writing. Hope it helps
The two numbers are -6 and 7
<em><u>Solution:</u></em>
Given that eight times a number plus five times another number is -13
The sum of two numbers is 1
To find: the two numbers
Let the two numbers be "a" and "b"
From given information,
Eight times a number plus five times another number = -13
eight times a number "a" + five times another number "b" = -13
8a + 5b = -13 ---- eqn 1
Also given that sum of two numbers is 1
sum of two numbers = 1
a + b = 1 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "b"</u></em>
From eqn 2,
a = 1 - b ----- eqn 3
Substitute eqn 3 in eqn 1
8(1 - b) + 5b = -13
8 - 8b + 5b = -13
8 - 3b = -13
-3b = -13 - 8
-3b = -21
<h3>b = 7</h3>
Substitute b = 7 in eqn 3
a = 1 - 7
<h3>a = -6</h3>
Thus the two numbers are -6 and 7
(6x^3)/(3(x+4))= 2x^3/(x+4)
Answer:
Based on what I can see, the answer is sixteenths.
Step-by-step explanation:
If you count every tick on the line, you can get the number sixteenths. Hope this helped :)
