5x/2 = 10/11
55x = 20
x = 4/11
**Not sure if I did this right I think I did
Answer:-3
Step-by-step explanation:
No, Brianna is not correct.
The distance around the pool is 131.4 ft
Step by step explanation:
1) Semi circle with a diameter equal to the side opposite it, 20 ft.
Find the length of half the circle:
Circumference of semi-circle = (1/2)(πd)
Where:
π = 3.14
d = 20 ft.
Circumference of semi-circle = (1/2)(3.14)(20 ft) = 31.4 ft.
2) Vertical lengths from the endpoint of semi-circle to the endpoints of horizontal lengths, 40 ft each ⇒ 2 × 40 ft. = 80 ft.
3.) Horizontal length at 20 ft.
Add the semi-circle, vertical, and horizontal lengths:
Distance around the pool = 31.4 ft + 80 ft. + 20 ft.
Distance around the pool = 131.4 ft.
The circumference is pi times the diameter of the circle. The radius is half of the diameter. In this case, the radius is then 36.
Answer:
Step-by-step explanation:
Since cotangent of angle is:
And
- cos λ = x/1, sin λ = y / 1
The value of cot λ is:
- cot λ = x/y = - 0.358/0.934 = - 0.383 (rounded)
Correct choice is B