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erma4kov [3.2K]
2 years ago
6

How can you use compensation to find 8 x 903?

Mathematics
1 answer:
Tasya [4]2 years ago
6 0
903 times 8 is 7224 hope it helped
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Solve (MAFS.912.A-REI.2.3)
Vikki [24]

Answer:

c,=2d=-2

Step-by-step explanation:

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2 years ago
Evaluate the following expression for x=-2 -4x+8+2x+3
sergiy2304 [10]

Answer:

15

Step-by-step explanation:

x = 2

-4x+8+2x+3 = ?

-4 (-2) + 8 + 2 (-2) + 3 =

= 8 + 8 - 4 + 3

= 16 - 4 + 3

= 12 + 3

= 15

hopefully this helped you :)

8 0
2 years ago
Derek says that the quotient of -2/7 divided by -2/21 is -1/3. Part A: What is the correct quotient? Part B: What mistake did De
Thepotemich [5.8K]

Answer:

The correct quotient is 3.

I think Derek has mistaken to divide -\frac{2}{21} by \frac{2}{7}.

Step-by-step explanation:

We have to check the quotient of (-\frac{2}{7})  \textrm{ divided by }(-\frac{2}{21}).

Part A:

Now, (-\frac{2}{7})  \textrm{ divided by }(-\frac{2}{21}).

= \frac{-\frac{2}{7} }{-\frac{2}{21} } =3

So, the correct quotient is 3.

Part B:

Derek says that the quotient is -\frac{1}{3}.  

So, I think Derek has mistaken to divide -\frac{2}{21} by \frac{2}{7}. (Answer)

8 0
2 years ago
Guys u have to help me im trying for one hour
Tpy6a [65]

Answer:

12 is the answers for the question

Step-by-step explanation:

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3 0
2 years ago
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How to construct a triangle with side lengths 10 cm and 14 cm and an angle between them of 60 degrees.
Yuliya22 [10]

Answer:

We draw line AB which is perpendicular to the 14 cm side

Since Angle C is 60 degrees that makes angle CAB = 30 degrees

Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm

Line BD equals 9 cm

Line AB^2 = 10^2 - 5^2 = 75

Line AD^2 = AB^2 + BD^2

Line AD^2 = 75 + 81

Line AD^2 = 156

Line AD = 12.4899959968

Line AB = Sqr root (75) = 8.6602540378

Angle D = arc sine  (8.6602540378 / 12.4899959968)

Angle D = 43.898 degrees

Angle A = 180 - 60 - 43.898 = 76.102 degrees

*****************************************************************

Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.

Step-by-step explanation:

4 0
2 years ago
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