3 years ago

(3x2 + 5x + 7) - (-4x2 + 3x - 6

Mathematics

1 answer:

ELEN [110]3 years ago

7 0

Answer:

7x2 + 2x + 13

Step-by-step explanation:

tiger algebra was used

https://www.tiger-algebra.com/drill/(3x2_5x_7)-(-4x2_3x-6)/

You might be interested in

PLEASE HELP QUICKLY IM NEED YOU!!! MATH QUESTION

coldgirl [10]

BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB I think

7 0

3 years ago

Read 2 more answers

Cot(90° − x) = 1 The value of x that satisfies this equation is Blank °.

Reil [10]

Answer:

$x=90\degree$

Step-by-step explanation:

The given trigonometric equation is

$\cos(90\degree -x)=1$

We take the inverse cosine of both sides to obtain;

$(90\degree -x)=\cos^{-1}(1)$

$(90\degree -x)=0$

Group similar terms t obtain;

$-x=0-90\degree$

$x=90\degree$

4 0

4 years ago

Read 2 more answers

1/3k+80=1/2k+120 k=??

Sati [7]

Answer:

The value of k is 240

Step-by-step explanation:

$\frac{1}{3}k + 80 = \frac{1}{2}k + 120$

Or, 120 - 80 = $\frac{k}{2} - \frac{k}{3}$

Or, 40 = $\frac{k}{6}$

So. k = 40 × 6 = 240

Hence The value of k is 240 Answer

3 0

4 years ago

In ΔIJK, the measure of ∠K=90°, KJ = 65, IK = 72, and JI = 97. What is the value of the cosine of ∠J to the nearest hundredth?

kow [346]

Answer:

$\cos(J) = 0.67$

Step-by-step explanation:

Given

$\angle K = 90^o$

$KJ = 65$

$IK = 72$

$JI = 97$

Required

$\cos(J)$

The question is illustrated with the attached image.

From the image, we have:

$\cos(J) = \frac{KJ}{JI}$

This gives:

$\cos(J) = \frac{65}{97}$

$\cos(J) = 0.67010309278$

$\cos(J) = 0.67$ --- approximated

7 0

3 years ago

2000:$5.00 2015:6.50 what is the change in the cost of the cheeseburger as a percent pls answer ASAP!! plsssssss

Salsk061 [2.6K]

23.18...........................

3 0

3 years ago