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ryzh [129]
3 years ago
7

How many solutions exist for the given equation? 12x+1=3(4x+1)-2

Mathematics
2 answers:
enyata [817]3 years ago
6 0
I got All Real Numbers (infinite answers); what's your answer choices?
vagabundo [1.1K]3 years ago
3 0
12x+1=3(4x+1)-2
12x=3(4x+1)-3
12x=12x+3-3
12x=12x

there are infinite solutions in that no matter what x is equal to, the equation will always be true (at least I think that's the answer...)
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il63 [147K]

Answer:

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Step-by-step explanation:

x^5y^2 − x^4y + 2xy^3 = 0

Applying the Product and Chain Rules:

y^2*5x^4*dx/dy + 2y*x^5 - (y*4x^3*dx/dy + x^4) + (y^3* 2*dx/dy + 3y^2*2x) =0

Separating the terms with derivatives:

y^2*5x^4*dx/dy - y*4x^3*dx/dy + y^3* 2*dx/dy =  x^4 -  2y*x^5 -  3y^2*2x

dx/dy =  (x^4 -  2x^5y -  6xy^2) /  (5x^4y^2 - 4x^3y +  2y^3)

7 0
3 years ago
Read 2 more answers
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sergiy2304 [10]

Answer:

A

Step-by-step explanation:

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3 0
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Mama L [17]

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Step-by-step explanation:

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Answer:

4

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8 0
3 years ago
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