Explanation:
Let, DG is the datagram so, DG= 2400.
Let, FV is the Value of Fragment and F is the Flag and FO is the Fragmentation Offset.
Let, M is the MTU so, M=700.
Let, IP is the IP header so, IP= 20.
Let, id is the identification number so, id=422
Required numbers of the fragment = ![[\frac{DG-IP}{M-IP} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7BDG-IP%7D%7BM-IP%7D%20%5D)
Insert values in the formula = ![[\frac{2400-20}{700-20} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2400-20%7D%7B700-20%7D%20%5D)
Then, = ![[\frac{2380}{680} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B2380%7D%7B680%7D%20%5D)
= ![[3.5]](https://tex.z-dn.net/?f=%5B3.5%5D)
The generated numbers of the fragment is 4
- If FV = 1 then, bytes in data field of DG=
and id=422 and FO=0 and F=1.
- If FV = 2 then, bytes in data field of DG= and id=422 and FO=85
and F=1.
- If FV = 3 then, bytes in data field of DG= and id=422 and FO=170
and F=1.
- If FV = 4 then, bytes in data field of DG=
and id=422 and FO=255
and F=0.
Answer: Backtracking
Explanation:
Backtracking algorithm approaches a solution in a recursive fashion whereby it tries to build answers and modify them in time intervals as we progress through the solution. One such backtracking algorithm is the N Queen problem whereby we place N Queen in a chessboard of size NxN such that no two queens attack each other. So we place a queen and backtrack if there is a possibility that the queen is under attack from other queen. This process continues with time and thereby it tends to extend a partial solution towards the completion.
The possible effect of malicious code cyber awareness 2022 is that It can
- damage or compromise digital files.
- Erase hard drive and give room for hackers access to PC.
<h3>What are malicious code?</h3>
They are codes that are dangerous to operation of our computer system and includes;
- viruses, trojan
- horses, worms
- macros
Learn more about effect of malicious code at:
brainly.com/question/17209742
Ben can use the "Appear" animation, but he has to make sure he sets the effect options to "By paragraph", otherwise all bullets appear at the same time. I'm sure Ben can figure that out.
The fraction of shipments that will be accepted is 0.1299.
<h3>
How to calculate the probability?</h3>
Probability of a defective DVD = 0.04
Using Binomial distribution,
Fraction of shipments accepted = Probability of zero defects in sample of 50 = P(X = 0)
= 50C0 * 0.040 * (1 - 0.04)⁵⁰
= 0.96⁵⁰
= 0.1299
Fraction of shipments accepted = Probability of zero or one defects in sample of 50 = P(X = 0) + P(X = 1)
= 50C0 * 0.040 * (1 - 0.04)50-0 + 50C1 * 0.041 * (1 - 0.04)50-1
= 0.9650 + 50 * 0.04 * 0.9649
= 0.4005
Learn more about probability on:
brainly.com/question/24756209
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