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SVEN [57.7K]
3 years ago
8

Common Tangents and AAA theorems

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0
You know from similar triangles that ...
  KM/KO = LM/LN
  (20 +x)/12 = x/8
Multiplying by 24, we get
  2(20 +x) = 3x
  40 +2x = 3x
Subtracting 2x, we get
  40 = x . . . . . . . . . . the measure of LM

The Pythagorean theorem tells us
  (LN)² +(NM)² = (LM)²
Substituting known values, this becomes
  8² +(NM)² = 40²
  (NM)² = 40² -8² = 1600 -64 = 1536
Then the measure of NM is ...
  NM = √1536 ≈ 39.19

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I need help I don’t understand and I need to show my work who would help me??
stich3 [128]

Answer: b

Step-by-step explanation:

In the last question, you wrote on a second equation "13x ...." kkk

Let's go:

We have to check each one answer in the following system:

x - 2y = 7

3x + 7y = 8

I can use the substituition method to solve this system...

x = 7 + 2y

3x + 7y = 8

3(7 + 2y) + 7y = 8

21 + 6y + 7y = 8

13y = 8 - 21

13y = -13

y = -1

x = 7 + 2.(-1)

x = 5

Finally, the correct answer is the second one (letter b).

5 0
3 years ago
Read 2 more answers
2,12,8 = 15<br>6, 14,4= 35<br>3,63,7= X​<br>FIND X
Karolina [17]

678899_778886282882

Step-by-step explanation:

hehw

4 0
3 years ago
How do you solve...3c^3d/9cd^-1
Maksim231197 [3]
<u>  3c³d  </u>  = <u>c²d²</u>
9cd^-1      3
4 0
4 years ago
DOG A dog is leashed to the corner of a house. How much running area does the dog have? Explain how you found your answer.
Eduardwww [97]

Answer:

The area will be \frac{3\pi r^{2} }{4}  where r is the length of the leash.

Step-by-step explanation:

The area of a circle is pi times the radius squared. One forth of that area is not available for the dog to run: its the corner of the house. so what's left is 3/4 of the area of the circle. (3/4)πr²

Since the length of the leash is not given in the question, no specific Area can be answered. Once that value is substituted for r, the actual area can be calculated.

7 0
3 years ago
Solve. (Enter your answer using interval notation.)<br> |3x + 15| &gt; 21
Katarina [22]

Answer:

(-∞, -12), (2, ∞)

or

(-∞, -12) U (2, ∞)

Step-by-step explanation:

|3x + 15| > 21, |3x + 15| < -21

3x + 15 > 21,  3x + 15 < - 21

     -15    -15         -15     -15

------------------   -------------------

3x > 6               3x < - 36

÷3  ÷3               ÷3     ÷3

------------         ------------------

x > 2                  x < -12

(-∞, -12), (2, ∞)

or

(-∞, -12) U (2, ∞)

I hope this helps!

4 0
1 year ago
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