Take half of the coefficient of x: It is 3, and half that is 3/2.
Then <span>x^2+3x=6 becomes:
</span><span> x^2+3x + (3/2)^2 =6 + (3/2)^2, and
(x+3/2)^2 = 6 + 9/4
You were not asked to solve the equation, but why not do it for the practice?
</span>Solve (x+3/2)^2 = 6 + 9/4 for x. There will be 2 values.
Adding together the shorter two sides results in 17 m. If these two sides were laid end to end, the sum of their sides (17 m) would be less than the length of the third side. Thus, NO triangle could be constructed with this set of line segments.
The answer to the question that needs to go on the top is 33
Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
