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Aleksandr [31]
3 years ago
6

A letter is selected from the words in accommodation list all the possible outcomes

Mathematics
1 answer:
Luda [366]3 years ago
8 0
Since a letter is selected from      a c c o m m o d a t i o n

Possible outcome:

It could be any of the thirteen letters. There are thirteen possibilities.

a      c     c     o       m     m     o     d     a    t      i     o     n          
You might be interested in
Please help asap!! (:
Verizon [17]
The answer should be letter B.
3 0
3 years ago
A baseball team batted 250 times during the season. During the season they got 120 hits, 60 strikeouts, 50 flyouts and 20 ground
GuDViN [60]

Answer:

52%

Step-by-step explanation:

250 TAB (Team At Bats)

120 TH (Team Hits)

130 TBO [60+50+20] (Team Batted Out)

130/250 = 52% or .52

7 0
3 years ago
Cathy conducted an experimentin which she placed red, yellow, blue, and orange pieces of paper in a hat and drew them out withou
Allisa [31]

Answer:

28/55

Step-by-step explanation:

First thing you do is add up all of the data values.

This is the total of everything you can draw.

in this case it would by 55.

We set this as the denominator and set the numerator to the ammount of times orange has been drawn.

This would result in our answer.

Hope this helps!

4 0
3 years ago
Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
If the first step in the solution of the equation -9 + x = 5x - 7 is "subtract x," then what would the next step be ?
lutik1710 [3]

Answer:

-1/2=x

Step-by-step explanation:

-9 + x = 5x - 7

     -x      -x

-9=4x-7

+7         +7

-2=4x

-2/4 =4x/4

-1/2=x

5 0
3 years ago
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