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2 years ago

Convert 32 ½ meters to feet

Mathematics

2 answers:

kozerog [31]2 years ago

6 0

32 1/2 to feet is 106 .63 :))

Olin [163]2 years ago

5 0

Answer: 32 1/2 meters = 106.63 ft

Step-by-step explanation: 1 meter is 3 ft and 3.37 inches, or 39.37 inches :)

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<img src="https://tex.z-dn.net/?f=Simplify%5C%3Beach%5C%3Bof%5C%3Bthe%5C%3Bfollowing%5C%3Bequations%5C%3Bfor%5C%3B50%5C%3Bpoints

jekas [21]

Answer:

y= -12
x = 7
q = -1
x = 24

Step-by-step explanation:

1. ..............................................

6(y + 7) = 2(y - 3)
6y + 42 = 2y - 6
6y - 2y = -6 - 42
4y = -48
y = -12

2...............................................

3x + 2(x - 5) = 25
3x + 2x - 10 = 25
5x = 25 + 10
5x = 35
x = 7

3 . ..............................................

10q + 3q + 5 = 2(q - 3)
13q + 5 = 2q - 6
13q - 2q = -6 - 5
11q = -11
q = -1

4. ..............................................

1/3(x + 6) = 2/3(x - 9)
3*1/3(x+6) = 3*2/3(x - 9)
x + 6 = 2(x - 9)
x + 6 = 2x - 18
2x - x = 6 + 18
x = 24

3 0

2 years ago

Read 2 more answers

Let f(x) be a continuous function such that f(1) and f'(x)-Vx3 + 6. What is the value of,f(5)? (A) 11.446 (C) 24.672 (B) 13.446

tia_tia [17]

Answer:

f(5) = 26.672 which is option D

Step-by-step explanation:

From question, f(1) = 2 and f'(x)=√(x^3 + 6)

f(5) = f(1) + (5,1)∫ f'(x) dx

Integrating using the boundary 5 and 1;

f(5) = 2 + (5,1)∫√(x^3 + 6) dx

f(5) = 2 + 24.672

So f(5) = 26.672

7 0

2 years ago

I would gladly appreciate it

IrinaVladis [17]

Answer: D

Step-by-step explanation: Complementary angles add up to 90 degrees supplementary add up to 180 degrees and vertical angles are like CAF and DAE like how they're diagonal

7 0

3 years ago

Read 2 more answers

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$