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3 years ago

Convert 32 ½ meters to feet

Mathematics

2 answers:

kozerog [31]3 years ago

6 0

32 1/2 to feet is 106 .63 :))

Olin [163]3 years ago

5 0

Answer: 32 1/2 meters = 106.63 ft

Step-by-step explanation: 1 meter is 3 ft and 3.37 inches, or 39.37 inches :)

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How do you find the area of the missing side

Margaret [11]

Lets use a rectangle as the example because I dont know what kind of shape you're looking for.

Area of a rectangle = length * width

Length (l) = 62

Width (w) = x

Area = 744

744 = 62 * x

Divide both sides by 62

744/62 = 12

12 = x

That means the width would equal 12

12 * 62 = 744

5 0

3 years ago

Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the

MAVERICK [17]

The functions are illustrations of composite functions.

The soil temperature at 2:00pm is 67

The given parameters are:

$\mathbf{I(h) =\frac{12h - h^2}{36}}$ ---- the function for sun intensity

$\mathbf{T(I) =\sqrt{5000I}}$ -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

$\mathbf{h = 2:00pm - 6:00am}$

$\mathbf{h = 8}$

Substitute 8 for h in $\mathbf{I(h) =\frac{12h - h^2}{36}}$ , to calculate the sun intensity

$\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}$

$\mathbf{I(8) =\frac{32}{36}}$

$\mathbf{I(8) =\frac{8}{9}}$

Substitute 8/9 for I in $\mathbf{T(I) =\sqrt{5000I}}$ , to calculate the temperature of the soil

$\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}$

$\mathbf{T(8/9) =\sqrt{4444.44}}$

$\mathbf{T(8/9) =66.67}$

Approximate

$\mathbf{T(8/9) =67}$

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

5 0

2 years ago

Heather is saving for retirement and has been doing a lot of research on how much she should put aside each month. The newest ar

tino4ka555 [31]

If Heather puts in 1.36% of her salary into a retirement account and she makes $63,000 in a year, this can be solved by 1.36% x 63000. First convert 1.36% into a decimal. To do this, divide by 100.

1.36/100=0.0136

1.36% x 63000
=0.0136 x 63000
=856.8
Heather would put $856.8 in for the whole year. To find how much per month, divide by 12.

856.8/12=71.4
Rounded to the nearest dollar is $71.

Heather would put $71 into a retirement account each month.

Note: This was solved by multiply the percent and then dividing by 12 months. You could also do this by dividing by 12 months first and then multiplying the percent.

6 0

3 years ago

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti

melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that $m = 100, \mu = \frac{1}{100} = 0.01$

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

$P(X > x) = e^{-\mu x}$

This is P(X > 190). So

$P(X > 190) = e^{-0.01*190} = 0.1496$

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

$P(X > x) = 0.08$