What is the answer to this question?

poizon [28]

ROC is often used when speaking about momentum, and it can generally be expressed as a ratio between a change in one variable relative to a corresponding change in another; graphically, the rate of change is represented by the slope of a line.

6 0

3 years ago

Triangles A B C and R M Q are shown. Angles C A B and M R Q are 29 degrees. Angles A B C and R M Q are 116 degrees. What additio

Svetlanka [38]

Answer:

Therefore, the two options for triangles to be congruent using AAS are

1. BC ≅ MQ (Additional information)

2. AC ≅ RQ (Additional information)

Step-by-step explanation:

Given:

∠CAB =∠MRQ = 29°

∠ABC = ∠RMQ = 116°

To Prove:

Δ ABC ≅ ΔRMQ by AAS congruence test which additional information is required

Proof:

In Δ ABC and Δ RMQ

∠CAB =∠MRQ = 29° ……….{Given}

∠ABC = ∠RMQ = 116° ..……..{Given}

BC ≅ MQ ……….{Additional information required}

Δ ABC ≅ Δ RMQ ….{By Angle-Angle-Side congruence test}

In Δ ABC and Δ RMQ

∠CAB =∠MRQ = 29° ……….{Given}

∠ABC = ∠RMQ = 116° ..……..{Given}

AC ≅ RQ ……….{Additional information required}

Δ ABC ≅ Δ RMQ ….{By Angle-Angle-Side congruence test}

Therefore, the two options for triangles to be congruent using AAS are

1. BC ≅ MQ (Additional information)

2. AC ≅ RQ (Additional information)

3 0

4 years ago

Read 2 more answers

What is the reciprocal of - 14/3

Delvig [45]

Answer:

3/14

Step-by-step explanation:

You basically flip the numbers around. Hope this helps!

7 0

3 years ago

Atraeus is solving the quadratic equation by completing the square. 7x2 – 14x + 6 = 0 7x2 – 14x = –6 A(x2 – 2x) = –6 What is the

Vedmedyk [2.9K]

So we first minus 6 both sides
7x^2-14x=-6
then we have
A(x^2-2x)=-6
what is A?

hmm (this should be painfully obvous, but if not, here are steps)

7x^2-14x=-6
A(x^2-2x)=-6

7x^2-14x=-6=A(x^2-2x)
7x^2-14x=A(x^2-2x)
undistribute 7
7(x^2-2x)=A(x^2-2x)
divide both sides by (x^2-2x)
7=A

A=7

3 0

4 years ago

Read 2 more answers

Post-test about graphs need help

Murrr4er [49]

Answer:

O A. $y=\frac{4}{3} x-\frac{1}{3}$