Question

Space Shuttle has three computers. Computer A is a primary computer and Computer B and Computer C are auxiliary computers. There is a constant probability of 3% that each computer might malfunction. What is the probability that during the operation of leaving orbit, primary computer fails, and one of the auxiliary computers will be in use?

Answer 1

Answer:

Required probability equals 0.18%

Step-by-step explanation:

The probability that the primary and one auxiliary computer fails equals

1) Probability that A and B fails

2)Probability that A and C fails

Thus required probability equals

$P(E)=P(1)(2)+P(1)P(3)\\\\P(E)=0.03\times 0.03+0.03\times 0.03P(E)=0.18%$