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lubasha [3.4K]
4 years ago
5

Can you subtract closed polynomials

Mathematics
2 answers:
leva [86]4 years ago
4 0
Polynomials are closed under addition. When subtracting polynomials, the variables and their exponents do not change. Only their coefficients will possibly change. ... Remember that the exponents in polynomials are whole numbers. When adding, distribute the positive (or addition) sign, which does not change any of the signs
netineya [11]4 years ago
3 0

Answer:

Polynomials are closed under addition. When subtracting polynomials, the variables and their exponents do not change. Only their coefficients will possibly change. This guarantees that the difference has variables and exponents which are already classified as belonging to polynomials.

Step-by-step explanation:

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A baseball team has a 162 game season, and has a goal to have an average attendance or 45,500 fans per game. To date, they have
cluponka [151]

Answer:

446.078431373= 447

Step-by-step explanation:

you will have to subtract 162 (the games in the season) and 60 (the game they have already played) that would give you 102 then you divide 45,500 by 102 and that would give you 446.078431373 which you round it up and you will get 447 people to reach their average.

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3 years ago
F(X) x-2/2 find FF(X)​
Whitepunk [10]

f(x) = \dfrac{x-2}{2}\\\\\\f(f(x)) = \dfrac{\dfrac{x-2}{2}-2}{2}\\\\\\f(f(x)) = \dfrac{\dfrac{x-2-4}{2}}{2}\\\\\\f(f(x)) = \dfrac{x-6}{4}

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3 years ago
Question 13 options:
natka813 [3]

Answer:

The jar has 32 dimes and 18 quarters

Step-by-step explanation:

<u>To solve this problem we can create a system of linear equations in terms of two-variables (say </u>x<u> and </u>y<u>) and solve it.</u> To begin let us analyze the problem further. We know that the values of each coin type are:

Dimes ( x )     = $0.10

Quarters( y )  = $0.25

Total Value   = $7.70

Total Coins   = 50

Now let us set up our system of equations as:

0.10x+0.25y=7.70      Eqn.(1)

x+y=50                     Eqn.(2)

Lets take Eqn.(2) and rerrange it to solve for x as:

x=50-y                     Eqn.(3)

Now lets plug this, in Eqn.(1) so we get the value of y as:

0.10(50-y)+0.25y=7.70\\\\5-0.10y+0.25y=7.70\\\\-0.10y+0.25y=7.70-5\\\\0.15y=2.7\\\\

y=\frac{2.70}{0.15} \\\\y=18

Plugging in y=18 back in Eqn.(3) we finally have:

x=50-18\\x=32

Thus we conclude that in the jar the coins are:

Dimes ( x ) =32

Quarters( y ) =18

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4 years ago
How do you solve linear equations using substitution
GuDViN [60]
You substitute the y from the second eqaution to the y in the first equation
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3 years ago
Rewrite the expression in a radical form k^2/9
GenaCL600 [577]
The numerator stays in the house and the denominator shows the power

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3 years ago
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