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just olya [345]
4 years ago
12

A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ . 5 √(13)

√(97)

Mathematics
1 answer:
slega [8]4 years ago
3 0

Answer:

\sqrt{13}\ units

Step-by-step explanation:

we have

R(1, -1), S(6, 1),T(8, 5),U(3, 3)

Plot the vertices

see the attached figure

The shorter diagonal is SU

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

S(6, 1),U(3, 3)

substitute

SU=\sqrt{(3-1)^{2}+(3-6)^{2}}

SU=\sqrt{(2)^{2}+(-3)^{2}}

SU=\sqrt{13}\ units

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