Question

A parallelogram whose vertices have coordinates R(1, -1), S(6, 1), T(8, 5), and U(3, 3) has a shorter diagonal of ___ . 5 √(13) √(97)

Answer 1

Answer:

$\sqrt{13}\ units$

Step-by-step explanation:

we have

$R(1, -1), S(6, 1),T(8, 5),U(3, 3)$

Plot the vertices

see the attached figure

The shorter diagonal is SU

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$S(6, 1),U(3, 3)$

substitute

$SU=\sqrt{(3-1)^{2}+(3-6)^{2}}$

$SU=\sqrt{(2)^{2}+(-3)^{2}}$

$SU=\sqrt{13}\ units$