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Lilit [14]
3 years ago
5

How many pounds of candy worth $8 per lb. should be mixed with 100 lb. of candy worth $4 per lb. to get a mixture that can be so

ld for $7 per lb.?
Mathematics
1 answer:
Gwar [14]3 years ago
5 0

Answer:

300 lbs

Step-by-step explanation:

Let x be the number of pounds of candy worth $8 per lb mixed

Now we have total pounds = 100+x

Value of the mixture = 100(4)+8x = 8x+400

Since 7 per lb to be sold out we get

\frac{8x+400}{100+x} =7\\8x+400 = 700+7x\\x=300

300 lbs should be mixed

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3 years ago
The volume of a rectangular box is 330 cubic inches. The length on one side of the top is 11 inches, and the height of the box i
Fiesta28 [93]

Answer: 110 square inches.

Step-by-step explanation:

The volume of a rectangular box would be:

V=length*width*height

In this case, we know the volume, the length and the height, and we don't know the width, so we're going to isolate it:

width=\frac{V}{length*height}

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This width is also the width of the top of the box, so the area of the top would be:

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3 years ago
A coin is tossed 11 times. a) How many different outcomes are possible? b) How many different outcomes have exactly 8 heads? c)
larisa86 [58]

Answer:

a) 2048

b)164

c)54

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Step-by-step explanation:

a) A coin has two faces.

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d) 7 heads= 11!/7!6! =39716800/3628800 = 11

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