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Lilit [14]
3 years ago
5

How many pounds of candy worth $8 per lb. should be mixed with 100 lb. of candy worth $4 per lb. to get a mixture that can be so

ld for $7 per lb.?
Mathematics
1 answer:
Gwar [14]3 years ago
5 0

Answer:

300 lbs

Step-by-step explanation:

Let x be the number of pounds of candy worth $8 per lb mixed

Now we have total pounds = 100+x

Value of the mixture = 100(4)+8x = 8x+400

Since 7 per lb to be sold out we get

\frac{8x+400}{100+x} =7\\8x+400 = 700+7x\\x=300

300 lbs should be mixed

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3. ** Over the course of July, the high temperatures of 6 random days were collected. The data is 2 shown below. 84°F 92°F 79°F
Tresset [83]

Given data:

The given table.

The expression for the average temperature is,

\begin{gathered} 86^{\circ}F=\frac{84^{\circ}F+92^{\circ}F+79^{\circ}F+x+82^{\circ}F+93^{\circ}F}{6} \\ 516^{\circ}F=430^{\circ}F+x \\ x=86^{\circ}F \end{gathered}

Thus, the value of x is 86 degree Fahrenheit.

7 0
1 year ago
The vendor of a coffee cart mixes coffee beans that cost $9 per pound with coffee beans that cost $5 per pound. How many pounds
lidiya [134]

Answer:

56.25 pound of the coffee that costs $5 per pound is needed

18.75 pound of the coffee that costs $9 per pound is needed

Step-by-step explanation:

Let the number of pounds be x and y respectively

The total pounds is 75;

So;

x + y. = 75 •••••••(i)

Total cost of first type

9 * x = $9x

Total cost of second type;

5 * y= $5y

75 pound at $6 per pound; total cost of this is;

6 * 75 = $450

Thus;

9x + 5y = 450 ••••••••(ii)

From i, x = 75-y

Put this into ii

9(75-y) + 5y = 450

675 -9y + 5y = 450

4y = 675-450

4y = 225

y = 225/4

y = 56.25

x = 75 - y from i

x = 75-56.25

x = $18.75

8 0
3 years ago
3x-8<23 and -4x+26>6
Papessa [141]

Answer:

3x-8<23 and -4x+26>6

x<31/3            x<5

Step-by-step explanation:

3x-8<23

Add 8 to both sides

3x<31

Then divide 3 to both sides

x<31/3


and -4x+26>6

Minus 26 to both sides

-4x>-20

You divide -4 to both sides

Keep in mind that everytime you divide a negative the inequality will change so > will be <

x<5

3 0
3 years ago
A class of 33 students elected a class treasurer. there were 111votes for candidate a and 15 votes for candidate
Advocard [28]

Since 111 is greater than 33, I will assume that you meant 11 votes for a candidate. Also, assuming that each student can vote only once, the answer would be

11/33 x 100=33.333333...

About 33.333 of the voters voted for candidate a.

3 0
3 years ago
Question 4
alina1380 [7]
For question 4 the answer is yes and for question 5 the answer is false
6 0
3 years ago
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