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BigorU [14]
3 years ago
9

Antwaun waters his lawn 3 times a week. If he watered his lawn 24 times in all, which equation could be used to find how many we

eks he has been watering his lawn?
(It's not 8, I know that) PLEASE HURRY
Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:

3x=24

Step-by-step explanation:

3 times a certain amount equals 24 times in total

MAXImum [283]3 years ago
3 0

Answer:

Antwanun waters his lawn 3 times a week, he watered his lawn 24 . So what you will need to do is divide 3 in 24 to find how many weeks he has been watering his lawn, You get 8. Mr. Antwanun has been watering for 8 weeks. Equation- Antuwantun waters his lawn 3 times a week so if he watered his lawn 24 times, 3 times a week he would have been watering his lawn for 8 weeks.

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Softa [21]

Answer:

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Step-by-step explanation:

Point slope form is y-y1=m(x-x1)

x1=9

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plug it all in!

y-0=-3(x-9)

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Hope this helps!

7 0
4 years ago
Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

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s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

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