T=(60cos78, 60sin78)
T=(12.47, 58.69)
C=45
d=√((45-12.47)^2+58.69^2)
d≈67.1km
Answer:
9-x
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let X be the length of pregnancy.
X is N(268, 15)
a) Prob of pregnancy lasting 307 days or longer
= P(X>307) = 
=0.5-0.4953
=0.0047
b) Lowest 2% is 2nd percentile
Z=-2.55
X score = 268-2.55(15)
= 229.75 days
If length of days >230 days then it is not premature.
3.15 will be your answer i am very sure of that