45 is the answer. It is the least common multiple of 5 and 9. Multiples of 5: 5, 10,15,20,25, 30, 35, 40, 45 and multiples of 9: 9, 18, 27, 36, 45

Distribute 3 throught the parentheses

Move the variable to the left-hand side and change its sign

Move the constant to the right-hand side and change its sign

Collect like terms

Divide both sides of the equation by -3

We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
Answer:
option a
option d
option e
Step-by-step explanation:
option a

option d

option e
