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4 years ago

What is the sale tax of a sweater for 36$ and a 7% sales tax

Mathematics

1 answer:

Ronch [10]4 years ago

5 0

36 × 0.07 = $2.52 sales tax

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Toby's little brother used his set of wooden blocks to build a giant tower. He stacked up 30 blocks to make a tower that was 64

dangina [55]

Solution to the question:

Number of blocks stacked: 30

Height of tower: 64 inches

Height of each block: ?

To find the height of each block, we divide the total height of the tower with the number of blocks stacked

Therefore,

Height of each block: 64/30 = 2.13 inches

So, the height of each block is 2.13 inches.

8 0

3 years ago

The table shows the precipitation in December, in inches, for Washington state from 2005 to 2013. What was the mean amount of pr

polet [3.4K]

Hello,
Please, see the attached file.
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3 years ago

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The third, fifth and eighth terms of an AP are the first 3 consecutive terms of a GP. Given that the first term of the AP is 8,

marshall27 [118]

Answer:

Common Difference = 2.

Step-by-step explanation:

An AP can be written as a1, a1 + d, a1 + 2d, a1 + 3d, a1 + 4d, a1 + 5d, a1 + 6d , a1 + 7d.

where a1 = first term and d is the common difference.

Here first term = a1 = 8

3rd term = a1 + 2d = 8 + 2d

5th term = a1 + 4d = 8 + 4d

8th term = 8 + 7d

First 3 terms of a GP are a , ar and ar^2

So from the given information:

a = 8 + 2d

ar = 8 + 4d

ar^2= 8 + 7d

Dividing the second equation by the first we have

r = (8 + 4d)/(8 + 2d)

Dividing the third by the second:

r = (8 + 7d) / (8 + 4d)

Therefore, eliminating r we have:

(8 + 4d)/(8 + 2d) = (8 + 7d)/(8 + 4d)

(8 + 4d)^2 = (8 + 2d)(8 + 7d)

64 + 64d + 16d^2 = 64 + 72d^ + 14d^2

2d^2 - 8d = 0

2d(d^2 - 4) = 0

2d = 0 or d^2 = 4, so

d = 0, 2.

The common difference can't be zero so it must be 2.

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3 years ago

PLS HELP PLS HELP PLS HELP

Lelu [443]

The answer is 3/22

Hope this help~

7 0

3 years ago

What is the product? 2y/y-3 x 4y-12/2y+6

Sphinxa [80]

Answer: The product of the above polynomials will be

$\frac{4y}{y+3}$

Step-by-step explanation:

Since we have given that

$\frac{2y}{y-3}\times \frac{4y-12}{2y+6}$

We need to solve the product of two polynomials :

$\frac{2y}{y-3}\times \frac{4y-12}{2y+6}\\\\=\frac{2y}{y-3}\times \frac{4(y-3)}{2(y+3)}\\\\=\frac{4y}{y+3}$

Hence, the product of the above polynomials will be

$\frac{4y}{y+3}$

8 0

3 years ago

Read 2 more answers