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ollegr [7]
3 years ago
8

Will give brainliest

Mathematics
2 answers:
Tamiku [17]3 years ago
6 0

Answer:

D. promoting general friendliness

Step-by-step explanation:

You are not invading someone's personal life. You are just being friendly.

Hope this helps! Please mark as brainliest.

KATRIN_1 [288]3 years ago
3 0

Answer:

D) promoting general friendliness

Step-by-step explanation:

You might be interested in
MATH HELP???
marin [14]
<h2>Answer:</h2>

The quadratic function are:

 option: A   A)  y(y + 4) - y = 6

 Option: C   C.)  4b(b) = 0

<h2>Step-by-step explanation:</h2>

We know that the general equation of a quadratic equation in terms of a variable x is given by:

   ax^2+bx+c=0

A)

y(y + 4) - y = 6

On simplifying the terms we have:

   y^2+4y-y=6\\\\y^2+3y-6=0

Hence, option: A is correct.

B)

(3x + 2) + (6x - 1) = 0

(3x + 2) + (6x - 1) = 0\\\\i.e.\\\\3x+2+6x-1=0\\\\i.e.\\\\3x+6x+2-1=0\\\\i.e.\\\\9x+1=0

Hence, it is a linear equation.

Hence, option: B is incorrect.

C)

4b(b) = 0

it could also be written as:

4b^2=0

Hence, it is a quadratic equation.

Hence, option: C is correct.

D)

3a - 7 = 2(7a - 3)

3a-7 = 2(7a-3)\\\\i.e.\\\\3a-7=14a-6\\\\\\i.e.\\\\14a-6-3a+7=0\\\\i.e.\\\\14a-3a-6+7=0\\\\i.e.\\\\11a+1=0

which is again a linear equation.

Hence, option: D is incorrect.

6 0
3 years ago
The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Need help on this I don't get it
Nataly [62]

Step-by-step explanation:

It is not a solution because the point falls outside the shaded region, if you were to plugin the point it would return a false statement

4 0
2 years ago
Which shows one way to determine the factors of x^3-12x^2-2x+24
SashulF [63]
Hello,
x^3-12x²-2x+24=x²(x-12)-2(x-12)=(x-12)(x²-2)
=(x-12)(x-√2)(x+√2)


8 0
3 years ago
What is the perimeter of a square with a length of 19 meters?
lord [1]
The answer is b 38cm
4 0
3 years ago
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