They need to admit 43 more cars to make at least $500
<u>Solution:</u>
Given, A drive in theater charges $3.50 per car,
The drive in already admitted 100 cars,
Then, money collected until now is $ 3.50 x 100 = $ 350
We have to solve an inequality to find the number of cars the drive in needs to admit to make atleast 500$
Now, let the number of cars need to be admitted be "n"
Then, inequality is:
collected amount + needed amount ≥ $ 500
$ 350 + $ 3.50 x n ≥ $ 500
350 + 3.5n ≥ 500
3.5n ≥ 500 – 350
On solving, we get
3.5n ≥ 150
n ≥ 42.857
As number of cars can’t be fractions, n = 43
Hence, they need to admit 43 more cars to make at least $500
Answer:
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Answer: 12 men would be needed to repair the same road in 3 1/3 hrs. Inverse proportion because usually in work,food and time its inversly proportional.
8 hours --> 5 men
1 hour --> 5*8 = 40 men
3 1/3 hours --> 40/ (3 1/3) men
--> 12 men
Answer:
x = - 6
Step-by-step explanation:
Given that y varies directly as x then the equation relating them is
y = kx ← k is the constant of variation
To find k use the condition y = - 9 when x = 3, thus
k = 
= 
= - 3
y = - 3x ← equation of variation
When y = 18, then
18 = - 3x ( divide both sides by - 3 )
x = - 6
