Answer:
yea its is
Step-by-step explanation:
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C




![\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]](https://tex.z-dn.net/?f=%5Ctext%7BFactor%3A%7D%5Cqquad%20%5Cqquad%20%5Cqquad%202%5Csin%20C%5Ccdot%20%5B%5Ccos%20%28A-B%29%2B%5Ccos%20%28A%2BB%29%5D)


LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C 
Answer:
Step-by-step explanation:
y = -4x^2 + 4x + 6
Factor out the leading coefficient:
y = -4(x^2 - x) + 6
Complete the square:
y = -4(x^2 - x + (½)^2) + 4(½)^2 + 6
= -4(x-½)^2 + 7
The reason behind the statement m∠TRS + m∠TRV = 180° is; Angle Addition Postulate
<h3>How to use angle addition postulate?</h3>
Angle addition postulate states that if D is the interior of ∠ABC, therefore, the sum of the smaller angles equals the sum of the larger angle, which from the attached image is;
m∠ABD + m∠DBC = m∠ABC.
From the attached image, we want to prove that x = 30°.
Now, T is the interior of straight angle ∠VRS.
m∠VRS = 180° (straight line angle)
Thus, from angle addition postulate, we can say that;
m∠TRS + m∠TRV = 180°.
Read more about two column proofs at;brainly.com/question/1788884
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