Ask question

Ask question

All categories

3 years ago

7

What is the volume of a cube whose edges each have a measure of 1.8 inches?

2 answers:

koban [17]3 years ago

8 0

<em>formula is a^3</em>

<em>a=edge</em>

<em>1.8^3=5.83in^3</em>

volume = 5.832

ratelena [41]3 years ago

7 0

Answer:

5.832 in³

Step-by-step explanation:

The volume (V) of a cube is

V = s³ ← s is the length of the side

here s = 1.8, thus

V = 1.8³ = 1.8 × 1.8 × 1.8 = 5.832 in³

You might be interested in

Solve for y. show work. 4(y+3)−2y+7

olga_2 [115]

Dude I don’t feel like working

5 0

3 years ago

Read 2 more answers

A ski resort has 18 inches of snow on the ground. The snow is falling at a rate of 4 inches per hour. which type of functions be

faust18 [17]

Answer:

Linear Function

$y=4x+18$

Step-by-step explanation:

Let

x----> the time in hours

y----> the total inches of snow on the ground

we know that

The function that best model this situation is the linear function

so

$y=mx+b$

In this problem

$m=4\frac{in}{h}$

$b=18\ in$ ----> the y-intercept

substitute

$y=4x+18$

4 0

3 years ago

Read 2 more answers

(6- -6 + 5.3) / -2.25

STALIN [3.7K]

Answer:

346 / 45

Step-by-step explanation:

6 + 6 + 5.3

9

----

4

4 0

3 years ago

One satellite is scheduled to be launched from Cape Canaveral in Florida, and another launching is scheduled for Vandenberg Air

Lisa [10]

Answer:

$P(A) = 0.45$

$P(B) = 0.32$

Step-by-step explanation:

Given

$P(A) > P(B)$

$P(A\ u\ B) = 0.626$

$P(A\ n\ B) = 0.144$

Required

Find P(A) and P(B)

We have that:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$ --- (1)

and

$P(A\ n\ B) = P(A) * P(B)$ --- (2)

The equations become:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$ --- (1)

$0.626 = P(A) + P(B) - 0.144$

Collect like terms

$P(A) + P(B) = 0.626 + 0.144$

$P(A) + P(B) = 0.770$

Make P(A) the subject

$P(A) = 0.770 - P(B)$

$P(A\ n\ B) = P(A) * P(B)$ --- (2)

$0.144 = P(A) * P(B)$

$P(A) * P(B) = 0.144$

Substitute: $P(A) = 0.770 - P(B)$

$[0.770 - P(B)] * P(B) = 0.144$

Open bracket

$0.770P(B) - P(B)^2 = 0.144$

Represent P(B) with x

$0.770x - x^2 = 0.144$

Rewrite as:

$x^2 - 0.770x + 0.144 = 0$

Expand

$x^2 - 0.45x - 0.32x + 0.144 = 0$

Factorize:

$x[x - 0.45] - 0.32[x - 0.45]= 0$

Factor out x - 0.45

$[x - 0.32][x - 0.45]= 0$

Split

$x - 0.32= 0 \ or\ x - 0.45= 0$

Solve for x

$x = 0.32\ or\ x = 0.45$

Recall that:

$P(B) = x$

So, we have:

$P(B) = 0.32 \ or \ P(B) = 0.45$

Recall that:

$P(A) = 0.770 - P(B)$

So, we have:

$P(A) = 0.770 - 0.32 \ or\ P(A) =0.770 - 0.45$

$P(A) = 0.45 \ or\ P(A) =0.32$

Since:

$P(A) > P(B)$

Then:

$P(A) = 0.45$

$P(B) = 0.32$

6 0

3 years ago

Which type of debt is often unsecured?

kramer

Answer: mortgage

Step-by Step explanation :

8 0

3 years ago