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WARRIOR [948]
3 years ago
7

What is the volume of a cube whose edges each have a measure of 1.8 inches?

Mathematics
2 answers:
koban [17]3 years ago
8 0

<em>formula is a^3</em>

<em>a=edge</em>

<em>1.8^3=5.83in^3</em>

volume = 5.832

ratelena [41]3 years ago
7 0

Answer:

5.832 in³

Step-by-step explanation:

The volume (V) of a cube is

V = s³ ← s is the length of the side

here s = 1.8, thus

V = 1.8³ = 1.8 × 1.8 × 1.8 = 5.832 in³

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3 years ago
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What is the unit rate of 588 and 12
leva [86]

Answer:

49

Step-by-step explanation:

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6 0
3 years ago
A survey of physicians in 1979 found that some doctors give a placebo to patients who complain of pain for which the physician c
lisov135 [29]
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5 0
3 years ago
PLEASE HELP
NeTakaya

Answer:

A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct

Step-by-step explanation:

step 1

Find the area of the base of the rectangular pyramid

we know that

The volume of the rectangular pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the base

H is the height of the pyramid

we have

V=40\ units^{3}

H=6\ units

substitute and solve for B

40=\frac{1}{3}B(6)

120=B(6)

B=120/6=20\ units^{2}

step 2

Find the volume of the rectangular prism with the same base area and height

we know that

The volume of the rectangular prism is equal to

V=BH

we have

B=20\ units^{2}

H=6\ units

substitute

V=(20)(6)=120\ units^{3}

therefore

The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct

3 0
3 years ago
A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What
vladimir2022 [97]

Answer:

The perimeter of the triangle is 12\ units

Step-by-step explanation:

Let

A(-3,1),B(1,1),C(1,-2)

we know that

The perimeter of triangle is equal to

P=AB+BC+AC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

A(-3,1),B(1,1)

substitute in the formula

AB=\sqrt{(1-1)^{2}+(1+3)^{2}}

AB=\sqrt{(0)^{2}+(4)^{2}}

AB=4\ units

step 2

Find the distance BC

B(1,1),C(1,-2)

substitute in the formula

BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}

BC=\sqrt{(-3)^{2}+(0)^{2}}

BC=3\ units

step 3

Find the distance AC

A(-3,1),C(1,-2)

substitute in the formula

AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}

AC=\sqrt{(-3)^{2}+(4)^{2}}

AC=5\ units

step 4

Find the perimeter

P=AB+BC+AC

substitute the values

P=4+3+5=12\ units

6 0
3 years ago
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