Answer:
Approximately 59 stacked cups.
Step-by-step explanation:
Given,
Height of a cup = 12.5 cm,
Two stacked cups = 14 cm,
Three stacked cups = 15.5 cm,
........, so on,....
Thus, there is an AP that represents the given situation,
12.5, 14, 15.5,....
First term is, a = 12.5,
Common difference, d = 1.5 cm,
Thus, the height of x cups is,
![h(x) = a+(x-1)d = 12.5 + (x-1)1.5 = 1.5x + 11](https://tex.z-dn.net/?f=h%28x%29%20%3D%20a%2B%28x-1%29d%20%3D%2012.5%20%2B%20%28x-1%291.5%20%3D%201.5x%20%2B%2011)
According to the question,
h(x) = 200
⇒ 1.5x + 11 = 200
⇒ 1.5x = 189
⇒ x = 59.3333333333 ≈ 59,
Hence, approximately 59 stacked cups will need.