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mixas84 [53]
3 years ago
14

The mean GPA in a class of 14 students is 3.12. One student, whose GPA is 2.41, drops the class. Two new students, whose GPAs ar

e 3.97 and 4.26, join the class.What is the new mean GPA of the class?
Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0
The mean would be 3.44.
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Answer:

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Step-by-step explanation:

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Translate the sentence into an inequality. Nine subtracted from the product of 4 and a number is greater than 17. Use the variab
nikdorinn [45]

Answer:

4y - 9 > 17

Step-by-step explanation:

Translate the sentence into an inequality. Nine subtracted from the product of 4 and a number is greater than 17. Use the variable y for the unknown number.

Unknown variable = y

Nine subtracted from the product of 4 and a number is greater than 17

4 multiplied by unknown variable 'y' = (4 * y) = 4y

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Then, the result is said to be greater than 17

4y - 9 > 17

Hence, The Inequality expression equivalent to the sentence above is 4y - 9 > 17

8 0
3 years ago
write an equation in slope intercept form for the line described. perpendicular to y = -1/2x + 2/3, passes through (2,3)
Alex17521 [72]

Step-by-step explanation:

Hey there!

Follow the steps to get answer.

  • Use one point formula and find 1st equation.
  • After that you find the slope of second equation.
  • Use the condition of perpendicular lines and find the slope of first equation.
  • Put slope value of equation in equation (i) and simplify them to get equation.

The equation of a line passing through point (2,3) is;

(y-3)= m1(x-2).......(i).

Another equation is;

y =  \frac{ - 1}{2} x +  \frac{2}{3}

2nd equation..

Now, From equation (ii)

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Comparing equation (ii) with y = mx+c.

We get;

Slope = -1/2.

For perpendicular lines,

m1 \times m2 =  - 1

m1 \times  \frac{ - 1}{2}  =  - 1

Therefore the slope is 2.

Put value of slope (m1) in equation (i). We get;

(y - 3) = 2(x - 2)

Simplify them to get equation.

(y - 3) = 2x - 4

y = 2x - 1

Therefore the required equation is y = 2x-1.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
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