Ask question

Ask question

All categories

3 years ago

14

The mean GPA in a class of 14 students is 3.12. One student, whose GPA is 2.41, drops the class. Two new students, whose GPAs ar

e 3.97 and 4.26, join the class.What is the new mean GPA of the class?

1 answer:

sertanlavr [38]3 years ago

3 0

The mean would be 3.44.

You might be interested in

The number of decimal places in the product will be sum of the factor"s decimal place.So the product will have 1,2,3 or 4 decima

vampirchik [111]

Answer:

$0.47 \to 2\ digits$

$3.2 \to 1\ digit$

$Product \to 3\ digits$

Step-by-step explanation:

Given

$0.47 * 3.2 =$

See comment for complete question

Required

The number of decimal places

To do this, we simply calculate the number of digits after the decimal points

$0.47 \to 2\ digits$

$3.2 \to 1\ digit$

The product is the sum of the digits above 2 + 1 = 3

Hence:

$Product \to 3\ digits$

6 0

3 years ago

I need to find the parent function and compare and contrast the domain and range of the parent function.

denpristay [2]

The parent function is f(x) = x^3 with domain = all real numbers and range = all real numbers.

The given function is f(x) = x^3 - 2 with domain = all real numbers and range = all real numbers.

8 0

3 years ago

Q8 Q18.) How many adults and students should attend to raise the maximum amount of money?

Kruka [31]

160 adults and 80 students seems to be correct

5 0

3 years ago

Read 2 more answers

On a coordinate plane, triangles R S T and L M N are shown. Triangle R S T has points (5, 5), (2, 1), and (1, 3). Triangle L M N

ivolga24 [154]

Answer:

LMN has a larger area

Step-by-step explanation:

Given

RST

$R =(5,5)$

$S= (2,1)$

$T = (1,3)$

LMN

$L = (0,-1)$

$M= (2,-4)$

$N= (-2,-3)$

Required

Compare both areas

The area of triangle is:

$Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|$

For RST, we have:

$Area = \frac{1}{2}|5*1 - 2*5 + 2*3 - 1*1 + 1*5 - 5*3|$

$Area = \frac{1}{2}|-10|$

Remove absolute signs

$Area = \frac{1}{2}*10$

$Area = 10$

For LMN, we have:

$Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3|$

$Area = \frac{1}{2}|0*-4-2*-1+2*-3--2*-4--2*-1-0*-3|$

$Area = \frac{1}{2}|-14|$

Remove absolute signs

$Area = \frac{1}{2}*14$

$Area = 7$

<em>By comparing both areas, we can conclude that LMN has a larger area</em>

3 0

3 years ago

Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (

natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{}_{} \int\limits^{}_D {x*y} \, dx*dy$

since D is the rectangle such that 0<x<3 , 0<y<3

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y} \, dx*dy = \int\limits^{3}_{0} {x} \, dx\int\limits^{3}_{0} {y} \, dy = x^{2} /2*y^{2} /2 = (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4$

4 0

3 years ago