Answer:
Step-by-step explanation:
it would be 60
Subsitte
y=6-x and y=x-2
both equal y so set equal;
6-x=y=x-2
6-x=x-2
add x both sides and addd 2
8=2x
divide 2
4=x
sub back
y=6-x
y=6-4
y=2
(x,y)
(4,2)
answer is C
The first false statement in the proof as it stands is in Line 5, where it is claimed that a line of length 2.83 is congruent to a line of length 4.47. This mistake cannot be corrected by adding lines to the proof.
_____
The first erroneous tactical move is in Line 4, where the length of DE is computed, rather than the length of FD. This mistake can be corrected by adding lines to the proof.
A correct SAS proof would use segment FD in Line 4, so it could be argued that the first mistake is there.
Answer:
Just put it into a calculator
0.97053528353
1. It's useful to divide out the GCF first because it makes factoring easier because the coefficients are smaller requiring less steps. 2. First, identify a,b, and c in the trinomial ax^2+bx+c. Then, write down all factor pairs of c Then, identify which factor pair from the previous step sums up to b. Then, Substitute factor pairs into two binomials 3. Key features are the y-intercept the zeros and the end behavior. to graph these put a pont on the intercepts and draw a line through them that matches the end behavior. 4. A binomial that is the difference of perfect squares is in the form of a^2-b^2 And its factor form is a^2 - b^2=(a-b)(a+b)5. Factoring by grouping often works well with four-term polynomials but the last step of factoring the common binomial only works when both terms contain the exact same binomial.
Should be right