The slope of the line that is perpendicular to 6x + 2y = -32 is: 1/3.
<h3>What is the Slope of Perpendicular Lines?</h3>
The slope of two lines that are perpendicular to each other will always have a product that is equal to -1, which means that their slopes are negative reciprocals to each other.
Rewrite 6x + 2y = -32 in slope-intercept form:
2y = -6x - 32
2y/2 = -6x/2 - 32/2
y = -3x - 16
The slope is -3. Negative reciprocal of -3 is 1/3.
Therefore, the slope of the perpendicular line would be: 1/3.
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So lets just assume that y = 1 since 2x is most likely an even number.
Then we can say that 2x = 8
8 divided by 2 is 4
so a point on this line could be (4,1)
Hope this helped
Answer:gchvbunonion
Step-by-step explanation:
Do you want to solve for x and y?
What is the objective?
3 √10
I think since a^2+b^2=c^2