Answer:
The sweat chloride reference value is less than 30 mmol/L. A value of more than 60 mmol/L of chloride in the sweat is consistent with a diagnosis of cystic fibrosis. The values of 30-60 mEq/L may represent heterozygous carriers, these carriers cannot be accurately identified with a sweat chloride test.
Answer:
2 hours = 4 * 30 minutes
30 * 3 = 90
90 * 3 = 270
270 * 3 = 810
810 * 3 = 2430
So after 2 hours you will have 2430 bacteria cells.
Step-by-step explanation:
Answer: D) 52%
Step-by-step explanation:
G = gymnastics
B = baseball
S = soccer
G = 28%
BA = 29%
S = 19%
G and BA = 14%
BA and S = 12%
G and S = 10%
GBS = 8%
So, as we can see at the Venn diagram attached (consider every number in %)
GBS = 8
A = G and S - GBS = 10 - 8 = 2
B = G and BA - GBS = 14 - 8 = 6
C = BA and S - GBS = 12 - 8 = 4
Only G = G - A - B - GBS = 28 - 2 - 6 - 8 = 12
Only BA = BA - B - C - GBS = 29 - 6 - 4 - 8 = 11
Only S = S - A - C - GBS = 19 - 2 - 4 - 8 = 5
So, 2+6+4+12+11+5+8 = 48
100 - 48 = 52%
<span>I know because 2:3 is the ratio for the first and when he gets 9 that is 3* more. So we multiply 3*2 of the red paint and we will get 6 </span>