To simplify you simply find common variables and add them together to get 56a^3b^3
Using the interest formulas, it is found that the values of the investment are given as follows:
- Using simple interest, the value will be of $34,000.
- Using compound interest, the value will be of $144,461.
- Using continuous compounding, the value will be of $148,002.
<h3>Simple Interest</h3>
Simple interest is used when there is a single compounding per time period.
The amount of money after t years in is modeled by:

In which:
- r is the interest rate, as a decimal.
In this problem, we have that the parameters are as follows:
P = 9000, r = 0.07, t = 40.
Hence:

<h3>Compound interest</h3>

n is the number of compounding, for quarterly n = 4, then:


<h3>Continuous compounding</h3>

Hence:

More can be learned about the interest formulas at brainly.com/question/25296782
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The answer is A:
Because the only difference between the rest of the answer choices are the lower and upper quartiles, that is all you need to find. In order to do so you find the median for the first half (lower quartile) and then find the median for the second half. In this case it is 29 (Q1) and 58 (Q2)
Answer:
They would meet each other at
PM.
Step-by-step explanation:
- Erik took a trip to see his friend Mike who lives 308 miles away.
- He left his place at 10 AM driving at 70 mph.
- In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.
As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means
Erik left his place at 12:00 PM noon.
so, at 12:00 PM Erik had already traveled:

Miles left 
Let 't' be the time when they meet
so





so
or
hour and
minutes after
noon
i.e.

Therefore, they would meet each other at
PM.
First we will convert those radian angles to degrees, since my mind works better with degrees. Let's work one at a time. First,

. If we start at the positive x-axis and measure out 315 we end up in the 4th quadrant with a reference angle of 45 with the positive x-axis. The side across from the reference angle is -1, the side adjacent to the angle is 1, and the hypotenuse is sqrt2. The cotangent of this angle, then is 1/-1 which is -1. As for the second one, converting radians to degrees gives us that

. Sweeping out that angle has us going around the origin more than once and ending up in the first quadrant with a reference angle of 30° with the positive x-axis. The side across from the angle is 1, the side adjacent to the angle is √3, and the hypotenuse is 2. Therefore, the secant of that angle is 2/√3.