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Nonamiya [84]
3 years ago
13

Given: 1 and 2 are supplementary angles Prove: l || m

Mathematics
1 answer:
alexandr1967 [171]3 years ago
8 0
Is there any way you could provide more information, a picture or something could be really helpful.
You might be interested in
What is the distance between the points (59.5, 34.2) and (15.3, 14.9)? Enter your answer rounded to the nearest tenth (0.1).
nirvana33 [79]

Answer:

48.2

Step-by-step explanation:

√(x2-x1)²+(y2-y1)²

√(15.3-59.5)² +(14.9-34.2)²

√(-44.2)² + (-19.3)²

√1953.64+372.49

√2326.13

48.2

5 0
2 years ago
Read 2 more answers
Three of these turtles weight 1,050 pounds. How much does one Pinta Island Tortoise weight?
aleksklad [387]

Answer:

350 pounds

Step-by-step explanation:

Assuming three of the turtles are Pinta Island Tortoise, then:

3 turtles -- 1050

1 turtle -- 1050/3 = 350

Thenks and mark me brainliest :))

8 0
3 years ago
Read 2 more answers
Find the inflation rate from 1992 to 1993 . Assume that all prices have risen at the same rate as the CPI.
Zinaida [17]

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420|

69,420

7 0
3 years ago
Can someone help me and explain? I will mark brainlest. ♡
Sedbober [7]

Answer:

p'(4) = -3

q'(8) = \frac{1}{4}\\

Step-by-step explanation:

For p'(4):

p(x) = f(x)g(x) \\ p'(x) = \frac{d}{dx}(f(x)g(x)) \\ p'(x) = f'(x)g(x) +f(x)g'(x)

p'(4) = f'(4)g(4) + f(4)g'(4) \\ p'(4) = (-1)(3) +(7)(0) \\ p'(4) = -3

For q'(8):

q(x) = \frac{f(x)}{g(x)} \\ q'(x)= \frac{d}{dx}(\frac{f(x)}{g(x)}) \\ q'(x) = \frac{f'(x)g(x) -f(x)g'(x)}{{g(x)}^2}

q'(8) = \frac{f'(8)g(8) -f(8)g'(8)}{{g(8)}^2} \\ q'(8) = \frac{(2)(2) -(6)(\frac{1}{2})}{{2}^2} \\ q'(8) = \frac{4 -3}{4} \\ q'(8) = \frac{1}{4}

4 0
3 years ago
Read 2 more answers
Given the following formula, with A = 27 and t = 3, solve for r. <br> A=p(1+rt)
Nookie1986 [14]

Answer:

<h2>A.r=\frac{27-p}{3p}</h2>

Step-by-step explanation:

The given formula is

A=p(1+rt)

Where A=27 and t=3

To solve for r, first we need to move p

\frac{A}{p}=1+rt

Then, we move the term 1

\frac{A}{p}-1=rt

Finally, we move the factor t

\frac{\frac{A}{p}-1 }{t} =r

Replacing given values, we have

\frac{\frac{27}{p}-1 }{3} =r\\r=\frac{\frac{27-p}{p} }{3} \\r=\frac{27-p}{3p}

Thereofre, the right answer is A.

7 0
3 years ago
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