Which inequality matches the graph?

Mathematics

1 answer:

loris [4]3 years ago

7 0

I feel like it is D, but I am not completely sure about that. If its wrong, I apologize.

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Cosx+1/sin^3x=cscx/1-cosx

ANTONII [103]

I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).


If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).


Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.


I hope this helps!

8 0

4 years ago

A circle with centre O has a radius of 6.2 cm.

Paul [167]

Answer:

it could either be 10.781 or 65.6, if not either of em then iam truly very sorry

Step-by-step explanation:

6 0

3 years ago

Mark raises guppies in an aquarium. He finds out that guppies reproduce very rapidly, and the number quadruples every month. He

Andrews [41]

For this case what we should know is that the function that best adapts to this problem is given by:
y = 2 * (4) ^ x
The graph of the function is shown for two different intervals:
A small interval of -1.5 to 0.5
A larger interval of -6.5 to 6.5.
In both intervals the exponential growth of the function is demonstrated.
Answer:
See attached image.