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4 years ago

6

What is the cube root of 64?

2 answers:

Keith_Richards [23]4 years ago

5 0

The cube root of 64 is 4

labwork [276]4 years ago

4 0

The cube rude of 64 is 4.

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Naily [24]

Answer:

x = 18

Step-by-step explanation:

Given $3 \sqrt[4]{(x-2)^3}-4 = 20$

now adding '4' on both sides, we get

$3 \sqrt[4]{(x-2)^3}-4+4= 20+4$

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i) $3 \sqrt[4]{(x-2)^3}$ = <u>24</u>

cancelling '3' on both sides, we get

$\sqrt[4]{(x-2)^3} = 8$

ii) $\sqrt[4]{(x-2)^3}$ = <u> 8</u>

<u>iii) </u> $(x-2)^{\frac{3}{4} } = 8$ <u></u>

<u></u> $(x-2)^{\frac{3}{4} } = 2^{3}$ <u></u>

iv) $(x-2)^\frac{3}{4} )^{\frac{1}{3} } = (2^{3})^\frac{1}{3}$

now simplify on both sides,we get

$(x-2)^\frac{1}{4} = 2$

$((x-2)^{\frac{1}{4} })^4 = 2^4$

simplify we get solution is

<u>v) (x-2) </u>= 16

<u>vi) final answer is x = 16 +2 =18</u>

<u></u>

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3 years ago

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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