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Likurg_2 [28]
4 years ago
5

How many 3/8ths are in 3 3/4ths?

Mathematics
2 answers:
slega [8]4 years ago
4 0

Answer:

6

Step-by-step explanation:

3/4×3=9/4

9/4÷3/8=

9/4×8/3=6

I hope it will be helpful

Vitek1552 [10]4 years ago
3 0

Answer:

10

Step-by-step explanation:

First make the fractions the same value:

3 and 3/4s is equal to

15/4 which is 30/8s

So,

10  3/8s go into 30/8s

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1/4x + 6 + 1/5x - 3/20x = 4.2
natta225 [31]

Answer:

6

Step-by-step explanation:

The explaination is in the picture

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4 years ago
7/9 - 1/2 in simplest fraction form
likoan [24]
14/18-9/18=5/18 it can't be simplified anymore
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3 years ago
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How do i do this type of slope?
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because it matters where the points are located

Step-by-step explanation:

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3 years ago
From the sum of 2 and -11, subtract the sum of 2 and -6<br>​
jolli1 [7]

Answer: -5

Step-by-step explanation: 2 + -11 = -9 and subtract -4 from it since it’s the sum of 2 + -6. -9 - -4 is -9 + 4 so -5

7 0
4 years ago
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Find the coordinates of the point 7/10 of the way from A to B. a=(-3,-6) b=(12,4)
Artemon [7]

Answer:

The coordinates of M are x = \frac{15}{2} and y = 1.

Step-by-step explanation:

Let be A = (-3,-6) and B = (12, 4) endpoints of segment AB and M a point located 7/10 the way from A to B. Vectorially, we get this formula:

\overrightarrow {AM} = \frac{7}{10}\cdot \overrightarrow {AB}

\vec M - \vec A = \frac{7}{10}\cdot (\vec B - \vec A)

By Linear Algebra we get the location of M:

\vec M = \vec A + \frac{7}{10}\cdot (\vec B - \vec A)

\vec M = \vec A +\frac{7}{10}\cdot \vec B - \frac{7}{10}\cdot \vec A

\vec M = \frac{3}{10}\cdot \vec A + \frac{7}{10}\cdot  \vec B

If we know that \vec A = (-3,-6) and \vec B = (12, 4), then:

\vec M = \frac{3}{10}\cdot (-3,-6)+\frac{7}{10}\cdot (12,4)

\vec M = \left(-\frac{9}{10},-\frac{9}{5}  \right)+\left(\frac{42}{5} ,\frac{14}{5} \right)

\vec M =\left(-\frac{9}{10}+\frac{42}{5} ,-\frac{9}{5}+\frac{14}{5}   \right)

\vec M = \left(\frac{15}{2} ,1\right)

The coordinates of M are x = \frac{15}{2} and y = 1.

6 0
3 years ago
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