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Pepsi [2]
3 years ago
7

Please help me I suck at math ​

Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

D.

Step-by-step explanation:

Find the slope.

Then the y int is 1

It also says less than or equal to

so you shade under

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Acellus inverse variation
RUDIKE [14]

The current when the resistance is 10 ohms is 24 amps

<h3>What are variations?</h3>

Variations are simply data that change in values (i.e. not constant)

<h3>Types of variation</h3>

The types of variations are:

  • Direct variation
  • Inverse variation
  • Joint variation
  • Combine variation

From the complete question (see attachment), we have the following highlights

  • The variation is an inverse variation
  • When current (I) is 30 amps, the resistance (R) is 8 ohms

An inverse variation is represented as:

k = IR

Where k represents the constant of variation.

The above equation can be rewritten as:

I_1R_1 = I_2R_2

So, we have:

30 \times 8 = I_2R_2

240 = I_2R_2

When the resistance is 10 ohms, we have:

240 = I_2 \times 10

Divide both sides by 10

24 = I_2

Rewrite the above equation as:

I_2 = 24

Hence, the current when the resistance is 10 ohms is 24 amps

Read more about inverse variation at:

brainly.com/question/1327394

8 0
3 years ago
What is the answer to this question<br> 3x+7=27
Strike441 [17]
Step 1) Add
7
to each side of the equation to isolate the
x
term while keeping the equation balanced:
3
x
−
7
+
7
=
27
+
7

3
x
−
0
=
34

3
x
=
34

Step 2) Divide each side of the equation by
3
to solve for
x
while keeping the equation balanced:
3
x
3
=
34
3

3
x
3
=
34
3

x
=
34
3
8 0
3 years ago
How do I solve (4x/7)-(5/6)
butalik [34]

Answer:

tgh

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
X/7-1=1-2/3y<br> HELPPPPP
olga2289 [7]

Answer:

-14/3y+ 14

Step-by-step explanation:

hope this helps

5 0
3 years ago
Determine whether the samples are independent or dependent. Upper A data set includes the weight of 140 students before and afte
Serhud [2]

Answer:

Option C)

Step-by-step explanation:

The samples are dependant.  There should be a relation between the weights of the students, even though there could be changes, as any value can go up or down. A student with a weight around of 30 has a higher chance of getting a weight around of 35 after the firts year than a student with weight around of 55. This means that the probability a student has for getting certain amount of weight after the first year may change depending on the weight the student had at the start of the year. You can therefore naturally relate the weight a student had before the first year with the weight the student had after the first year.

So, the samples are dependant because there is a natural pairing between the to samples, as option C says.

7 0
3 years ago
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